Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Two masses m1=6 kg and m2 = 4 kg are connected by a light string that passes over a smooth pulley on a smooth inclined plane; The system is at rest; The normal reaction force acting on the mass is?

Two masses m1=6 kg and m2 = 4 kg are connected by a light string that passes over a smooth pulley on a smooth inclined plane; The system is at rest; The normal reaction force acting on the mass is?

Option: 1

20\sqrt{5}N


Option: 2

10\sqrt{5}N


Option: 3

15\sqrt{5}N


Option: 4

12\sqrt{5}N


Answers (1)

best_answer

From the system, we can say that

m_{2}g=m_{1}sin\theta

\Rightarrow sin\theta =\frac{4}{6}=\frac{2}{3}
\Rightarrow cos\theta =\frac{\sqrt{5}}{3}

Reaction Force

N=m_{1}g\, cos\theta
\Rightarrow N=\frac{\sqrt{5}}{3}*6*10=20\sqrt{5}N

Posted by

Pankaj

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET 2026 registration deadline extended to March 11 for MBBS, BDS; exam on May 3
anam-khan

NEET 2026 Registration LIVE: NTA extends MBBS, BDS application deadline to March 11; exam date
anam-khan

NEET: CBI takes over case of aspirant's death in Patna hostel; FIR registered

Latest Question