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Two point light sources are 24cm apart. At what distance from one source, a convex lens of focal length 9cm be kept in between them, so that the images of both the sources are formed at the same place.

Option: 1

6cm


Option: 2

9cm


Option: 3

12cm


Option: 4

15cm


Answers (1)

best_answer

The given condition will be satisfied only if one source \left(\mathrm{S}_1\right)  placed on one side such that u<f (i.e. it lies under the focus). The other source \left(\mathrm{S}_2\right)  is placed on the other side of the lens such that u>f (i.e. it lies beyond the focus).
If \left(\mathrm{S}_1\right) is the object for lens then

\mathrm{\frac{1}{f}=\frac{1}{-y}-\frac{1}{-x} \Rightarrow \frac{1}{y}=\frac{1}{x}-\frac{1}{f} \text {. }}....................(i)

If \mathrm{S_2} is the object for lens then

\mathrm{\frac{1}{f}=\frac{1}{+y}-\frac{1}{-(24-x)} \Rightarrow \frac{1}{y}=\frac{1}{f}-\frac{1}{(24-x)}}.....................(ii)

From equation (i) and (ii)

\mathrm{\frac{1}{x}-\frac{1}{f}=\frac{1}{f}-\frac{1}{(24-x)}}


\mathrm{ \Rightarrow \quad \frac{1}{x}+\frac{1}{(24-x)}=\frac{2}{f}=\frac{2}{9} \\ }

\mathrm{ \Rightarrow x^2-24 x+108=0 }

On solving we have  \mathrm{ x=18 \mathrm{~cm}, 6 \mathrm{~cm} }.

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Gunjita

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