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Two point masses m and 2m are joined by light rod of length d. The moment of inertia of the system about an axis passing through its centre of mass and making an angle 30° with the light rod will be

Option: 1

\frac{md^{2}}{3}
 


Option: 2

\frac{md^{2}}{6}


Option: 3

\frac{md^{2}}{4}

 


Option: 4

\frac{md^{2}}{2}


Answers (1)

best_answer

Answer (2)

r_{1}=\frac{m\times 0+2md}{3m}

r_{1}=\frac{2d}{3}

r_{2}=d-\frac{2d}{3}

     =\frac{d}{3}

I=m\left ( \frac{2d}{3}\sin 30^{o} \right )^{2}+2m\left ( \frac{d}{3}\sin 30^{o} \right )^{2}

I=\frac{md^{2}}{9}+\frac{md^{2}}{18}

=\frac{3md^{2}}{18}

=\frac{md^{2}}{6}

Posted by

Sanket Gandhi

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