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Two points A and B are spearated by a distance of 5cm respectively 15o C and 35o C respectively then temprature gradient (in oC /m) will be 

Option: 1 400

Option: 2 200

Option: 3 600

Option: 4 800

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As we have learned

Temperature Gradient -

Rate of change of temperature with position between two isothermal surface.

- wherein

 

 Temprature gardient = \frac{\Delta T}{\Delta x} = \frac{35 ^{\circ}C-15^{\circ}C}{5cm}= 400 ^{\circ}C/m

 

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Anam Khan

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