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  • Two radio broadcast their programmes at same amplitude A at slightly different frequencies <img alt="\omega_1 \text { and } \omega_2\left(\omega_1-\omega_2=10^3 \mathrm{~Hz}\right) \text {. }"

Two radio broadcast their programmes at same amplitude A at slightly different frequencies \omega_1 \text { and } \omega_2\left(\omega_1-\omega_2=10^3 \mathrm{~Hz}\right) \text {. }

A detector is receiving signals from the two stations simultaneously. It can only detect signal of intensity >2 A^2. The time interval between successive maxima of the intensity of the signal received by the detector is 

Option: 1

10^3 \mathrm{sec}


Option: 2

10^{-3} \mathrm{sec}


Option: 3

10^{-4} \mathrm{sec}


Option: 4

10^4 \mathrm{sec}


Answers (1)

best_answer

\pi\left(\omega_2-\omega_1\right) t=0, \pi, 2 \pi \ldots

\text { i,e } t=0, \frac{1}{\omega_2-\omega_1}, \frac{2}{\omega_2-\omega_1}

So, time interval between two consecutive maxima, 

=\frac{1}{\omega_2-\omega_1}=\frac{1}{10^3}=10^{-3} \mathrm{sec}

 

Posted by

Gautam harsolia

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