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  • two trains of A and B of length 400 m each are moving

phy1.PNG Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km/h in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates byl m/s2. If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?

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 the guard at the rear of B is passing the driver at the front of A then B has not only caught up the initial distance between the two trains but has also completely overtaken train A.  
Let the original separation distance be x. Then distance to be covered starting with relative velocity zero is s = 800 + x (800m being the overtaking distance from front meets rear to rear leaves front). 
Distance s covered at acceleration a starting from (relative) speed zero = 1/2 at^2 which for t=50 gives: 
= 0.5 x 50^2 = 1250m 
So 800 + x = 1250 Therefore x = 1250 -800 = 450m.

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Safeer PP

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