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  • Two vessels separately contain two ideal gases A and B at the same temperature; the pressure of A being twice that of B. Under such conditions, the density of A is found to be 1.5 times the density

Two vessels separately contain two ideal gases A and B at the same temperature; the pressure of A being twice that of B. Under such conditions, the density of A is found to be 1.5 times the density of B. The ratio of molecular weight of A and B is:

Option: 1

\frac{3}{4}


Option: 2

2


Option: 3

\frac{1}{2}


Option: 4

\frac{2}{3}


Answers (1)

best_answer

 

Ideal gas equation PV=nRT

OR PM=\rho RT

where M= Molecular \:weigh

\rho = \: density

{For \:A}= P_A.M_A=\rho _ART

{For \:B}= P_B.M_B=\rho _BRT

Divide the two equation

\frac{P_AM_A}{P_BM_B}=\frac{\rho _A}{\rho _B} .......(1)

Given  P_A= 2P_B

P_A= 1.5P_B

\therefore \frac{M_A}{M_B}=(\frac{\rho _A}{\rho _B})(\frac{\rho _B}{\rho _A})

=(1.5)(\frac{1}{2}) =\frac{3}{4}

 

Posted by

manish

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