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Under a constant pressure head, the rate of streamlined volume flow of a liquid through a capillary tube is Q. If the length of the capillary tube is doubled and the diameter of the bore is halved, the rate of flow would become

Option: 1

\mathrm{Q / 4}


Option: 2

\mathrm{Q / 8}


Option: 3

\mathrm{Q / 16}


Option: 4

\mathrm{Q / 32}


Answers (1)

best_answer

The rate of flow is given by

                               \mathrm{ Q=\frac{\pi P r^4}{8 \eta l} }
If l is doubled and r is halved, the rate of flow will become \mathrm{\left(\frac{1}{2}\right)^4 \times \frac{Q}{2}=\frac{Q}{32}} .

Hence the correct choice is (d).

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manish

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