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  • Water is flowing steadily through a horizontal tube of non uniform cross-section. If the pressure of water is <img alt="4 \times 10^4 \mathrm{~N} / \mathrm{m}^2" src="https://entrancecorner.oncodec

Water is flowing steadily through a horizontal tube of non uniform cross-section. If the pressure of water is 4 \times 10^4 \mathrm{~N} / \mathrm{m}^2 at a point where cross-section is 0.02 \mathrm{m}^2 and velocity of flow is 2 \mathrm{~m} / \mathrm{s}, what is pressure at a point where cross-section reduces to 0.01 \mathrm{~m}^2

Option: 1

\mathrm{1.4 \times 10^4 \mathrm{~N} / \mathrm{m}^2}


Option: 2

\mathrm{3.4 \times 10^4 \mathrm{~N} / \mathrm{m}^2}


Option: 3

\mathrm{2.4 \times 10^4 \mathrm{~N} / \mathrm{m}^2}


Option: 4

\mathrm{None \, \, of \, \, these}


Answers (1)

best_answer

\mathrm{\begin{aligned} & A_1 V_1=A_2 V_2 \\\\ & 0.02 \times 2=0.01 \times V_2 \\\\ & V_2=4 \mathrm{~m} / \mathrm{sec} \\\\ & P_1+\frac{1}{2} \rho V_1^2=P_2+\frac{1}{2} \rho V_2^2 \\\\ & 4 \times 10^4+\frac{1}{2} \times 1000 \times 2^2 \\\\ & =P_2+\frac{1}{2} \times 1000 \times 4^2 \\\\ & P_2=3.4 \times 10^4 \mathrm{~N} / \mathrm{m}^2 \end{aligned}}

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Gautam harsolia

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