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Water is flowing through two horizontal pipes of different diameters which are connected together. The diameter of the two pipes are 3 \mathrm{~cm} and 6 \mathrm{~cm} respectively. If the speed of water in narrower pipe is \mathrm{4 \mathrm{~m} / \mathrm{sec}} and the pressure is 2.0 \times 10^{\wedge} 4 pascal, then the speed of water in the wide pipe is:

Option: 1

4 \mathrm{~m} / \mathrm{sec}
 


Option: 2

\mathrm{2 \mathrm{~m} / \mathrm{sec}}
 


Option: 3

1 \mathrm{~m} / \mathrm{sec}
 


Option: 4

16 \mathrm{~m} / \mathrm{sec}


Answers (1)

best_answer

\mathrm{\begin{aligned} & A_1 V_1=A_2 V_2 \\\\ & \Rightarrow \pi\left(\frac{3}{2}\right)^2 \cdot 4=\pi\left(\frac{6}{2}\right)^2 \cdot V_2 \\\\ & \Rightarrow V_2=1 \cdot \mathrm{m} / \mathrm{s} \end{aligned}}

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manish painkra

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