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Water rises to a height h in a capillary tube of area of crosssection a. To what height will water rise in a capillary tube of area of cross-section 4a?

Option: 1

\mathrm{\frac{h}{4}}


Option: 2

\mathrm{\frac{h}{2}}


Option: 3

\mathrm{2 h}


Option: 4

\mathrm{4 h}


Answers (1)

best_answer

Area of cross-section \mathrm{a=\pi r^2.} Therefore \mathrm{r=\sqrt{a / \pi}}. In terms of a, the height to which a liquid rises in a capillary tube, is given by

\mathrm{ h=\frac{2 \sigma \cos \theta}{r \rho g}=\frac{2 \sqrt{\pi} \sigma \cos \theta}{\sqrt{a} \rho g} }
Thus, h is inversely proportional to \mathrm{\sqrt{a}.} If a is increased 4 times, h will decrease by a factor of 2 .

Posted by

Irshad Anwar

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