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  • What is the change in oxidation number of carbon in the following reaction ? <img alt="\mathrm{CH_{4}(g)+4Cl_{2}(g)\rightarrow CCl_{4}(l)+4HCl(g)}" src="https://entrancecorner.oncodecogs.

What is the change in oxidation number of carbon in the following reaction ?

\mathrm{CH_{4}(g)+4Cl_{2}(g)\rightarrow CCl_{4}(l)+4HCl(g)}

Option: 1

 0 to -4


Option: 2

 +4 to +4


Option: 3

 0 to +4

 


Option: 4

 -4 to +4


Answers (1)

best_answer

In \mathrm{CH_{4}} the oxidation number of carbon is -4 while in \mathrm{CCl_{4}} the oxidation number of Carbon is +4.

Hence, the oxidation state changes from -4 to +4.

Therefore, Option(4) is correct.

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mansi

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