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What is the difference b/w nth second and n seconds and how to solve solve respective problems?

Answers (3)

best_answer

@ Harshita 

distancetravelled in nth second=(distance travelled in n seconds)-(distance travelled in (n-1) seconds)

                                                 =S_{n}- S_{n-1}  =    u(n)+ (1/2)a(n)^2- u(n-1)+ (1/2)a(n-1)^2

                                                   =u + (1/2)a(2n-1)

Posted by

avinash.dongre

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@ Harshita

let U=5m/s and a=2ms^{-2}

then distance-travelled in 4th second=(distance travelled in 4seconds)-(distance travelled in (3) seconds)

                                                           = 5 + (1/2)*2*(7)=12 m

Posted by

avinash.dongre

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@ Harsita 

 

Test

\frac{a}{v} test

The electrophilic intermediate that attacks the benzene ring in the above reaction is.

Image result for nth second

Posted by

sudhir.kumar

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