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  • What volume (in L) of 0.2 M FeSO4 can be oxidized by a current of 0.965 ampere in an hour?Option: 1 0.1<div class='qna-

What volume (in L) of 0.2 M FeSO4 can be oxidized by a current of 0.965 ampere in an hour?

Option: 1

0.1


Option: 2

0.09


Option: 3

0.08


Option: 4

0.07


Answers (1)

best_answer

 1 \mathrm{\: F}=96500 \mathrm{\: C}=1 \text { equivalent of } \mathrm{Fe}^{2+}   
\left(\mathrm{n} \text { factor } \mathrm{Fe}^{2+}=2\right)
\begin{array}{l}{0.965 \times 3600 \mathrm{{\: C}=\frac{0.965 \times 3600}{96500}=\frac{36}{1000} \text { equivalent }}} \\\\ \mathrm{V(\text { in } \mathrm{L}) \times N=\text { Equivalent }} \\\\ \mathrm{V(\text { in } \mathrm{L}) \times 2 \times 0.2=\frac{36}{1000}} \\\\ \mathrm{V(\text { in } \mathrm{L})=\frac{36}{1000 \times 2 \times 0.2}=0.09 \mathrm{\: L}}\end{array}

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manish painkra

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