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  • What volume of O2 is obtained at STP, when 12.25 g of KClO3 is decomposed accordin

What volume of O2 is obtained at STP, when 12.25 g of KClO3 is decomposed according to the reaction (Molar mass of KClO3= 122.5 g/mol)

\mathrm{KClO}_{3} \stackrel{\Delta}{\longrightarrow} \mathrm{KCl}+\frac{3}{2} \mathrm{O}_{2}

Option: 1

22.4 L


Option: 2

11.2 L


Option: 3

3.36 L


Option: 4

44.8 L


Answers (1)

best_answer

1 mole of KClO3 produces 1.5 moles of O2

So, 0.1 mole of KClO3 will produce 0.15 moles of O2

Thus, volume = 22.4 X 0.15 = 3.36L

Therefore, Option(3) is correct.

Posted by

Gautam harsolia

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