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  • What will be the number of protons in the nucleus of the system when a single election system has ionization energy <img alt="11160 \mathrm{~kJ} / \mathrm{mol}" src="/latex-image/?11160%20%5Cmathrm

What will be the number of protons in the nucleus of the system when a single election system has ionization energy 11160 \mathrm{~kJ} / \mathrm{mol}.

Option: 1

4


Option: 2

2


Option: 3

3


Option: 4

5


Answers (1)

best_answer

\mathrm{I.E(\mathrm{KJ} / \mathrm{mol})=1312.3 \mathrm{KJ} / \mathrm{mol} \text {. }}

\mathrm{ { I.E_{H\; like atom} }={ I. E_{H\; atom} } \times z^2}

\mathrm{z^2=\frac{11160}{1312}=8.5}

\mathrm{z=\sqrt{8.5}=2.82 \simeq 3 .}

\therefore no. of protons in nucleus of system = 3

Option (3) is right answer.

Posted by

Ajit Kumar Dubey

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