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  • When a mixture of Hydrogen and Helium has total volume . and temperature

When a mixture of Hydrogen and Helium has total volume 1000 \mathrm{~cm}^3. and temperature 200 K, Pressure 400 kPa, and mass 0.8 g find the Ratio of masses Helium to Hydrogen

Option: 1

1:4


Option: 2

4:1


Option: 3

3:4


Option: 4

4:3


Answers (1)

best_answer

\begin{aligned} & \mathrm{P V=n R T} \\ & 400 \times 10^3 \times 1000 \times 10^{-6}=\mathrm{n \times\left(\frac{25}{3}\right) \times 200} \\ & \mathrm{4=n \times \frac{25}{3} \times 2} \\ & \mathrm{6=25 \: n} \\ & \mathrm{n=\frac{6}{25}} \end{aligned}

Let us assume \mathrm{n_{1}\; and \; n_{2}} mole of Hydrogen and Helium.

\begin{aligned} & \mathrm{n_1+n_2=n} \\ \\& \mathrm{n_1-\frac{\text { Given mass }}{\text { molar mass }} }\\ \\& \mathrm{\frac{m_1}{2}+\frac{m_2}{4}=\frac{6}{25}} \end{aligned}

\begin{aligned} & \mathrm{2 m_1+m_2=\frac{24}{25}=0.96} \\ \\& \mathrm{m_1+m_2=0.8} \\ \\& \mathrm{m_1=0.16} \\ \\& \mathrm{m_2=0.64} \\ \\& \mathrm{ \frac{m_2}{m_1}=\frac{0.64}{0.16}=\frac{4}{1}=4: 1} \end{aligned}

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Divya Prakash Singh

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