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When an ideal diatomic gas is heated at constant pressure, the fraction of the heat energy supplied which increases the internal energy of the gas is -

Option: 1

\frac{5}{7}


Option: 2

\frac{3}{7}


Option: 3

\frac{7}{3}


Option: 4

\frac{7}{5}


Answers (1)

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When a gas is heated at constant pressure then it's one part goes to increase the internal energy and another part for work done against external pressure

\begin{aligned} & \text { i.e. } \\ & (\Delta Q)_{P}=\Delta U+\Delta \omega \\ \Rightarrow \mu c_{P} \Delta T & =\mu c_{V} \Delta T+P \Delta V \end{aligned}

So the fraction of energy that goes to increase the internal energy,

\frac{\Delta u}{(\Delta Q)_{P}}=\frac{c_{v}}{c_{P}}=\frac{1}{r}=\frac{5}{7} \text { (as } r=\frac{7}{5} \text { for diatomic gas) }
 

Posted by

HARSH KANKARIA

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