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  • When  gas is passed through a solution of <img alt="\mathrm{K}_2 \mathrm{Cr}_2 \mat

When \mathrm{SO_{2}} gas is passed through a solution of \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7, the oxidation state of sulphur and chromium in the products are:

Option: 1

+6, +4


Option: 2

+3, +6


Option: 3

+6, +3


Option: 4

+3, +4


Answers (1)

best_answer

\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{SO}_2+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{K}_2 \mathrm{SO}_4+\mathrm{Cr}_2\left(\mathrm{SO}_4\right)_3+\mathrm{H}_2 \mathrm{O}

Oxidation number of Cr in \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 is +6 and in \mathrm{Cr}_2\left(\mathrm{SO}_4\right)_3 is +3. Oxidation number of S in \mathrm{SO_{2}} is +4 and in \left(\mathrm{SO}_4\right)^{2-} ion is +6.

Posted by

HARSH KANKARIA

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