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  • When two progressive waves  and <img alt="Y_{2 }= 6

When two progressive waves Y_{1 }= 13 sin (4x-8t) and Y_{2 }= 6sin (4x-8t -\frac{\Pi }{2}) are superimposed, the amplitude of thee resultant wave?

Option: 1

8


Option: 2

6


Option: 3

7


Option: 4

5


Answers (1)

best_answer

As we know that,

\begin{aligned} & \Delta \Theta =\theta_1-\theta_2=\frac{\pi}{2} \\ & \text { Ar }=\sqrt{(\sqrt{13})^2+(6)^2+2 \times \sqrt{13} \times 6 \cos \frac{\pi}{2}} \\ & \text { Ar }=\sqrt{13+36+2 \times \sqrt{13} \times 66+\frac{\pi}{2}} \\ & \text { Ar }=\sqrt{49+2 \times \sqrt{13} \times 6 \times 0} \quad\left[\because \cdot at\frac{\pi}{2}=0\right] \\ & \text { Ar }=\sqrt{49+0} \\ & \text { Ar }=\sqrt{49} \\ & \text { Ar }=7 \end{aligned}

Posted by

Gautam harsolia

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