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  • Which among the following is correct order of the size of <img alt="Ca^{2+}< K^{+}< Ar< Cl^{-}< S^{2-}" src="/latex-image/?Ca%5E%7B2&plus;%7D%3C%20K%5E%7B&plus;%7D%3C%20Ar%3C%20

Which among the following is correct order of the size of Ca^{2+}< K^{+}< Ar< Cl^{-}< S^{2-}

Option: 1

Ca^{2+} < K^+ < Ar < Cl^-< S^{2-}


Option: 2

Ar < Ca^{2+} < K^+ < Cl^-< S^{2-}


Option: 3

Ca^{2+} < Ar < K^+ < Cl^- < S^{2-}


Option: 4

Ca^{2+} < K^+ < Ar < S^{2-} < Cl^-


Answers (1)

The given species are isoelectronic species. We know that among the isoelectronic species, the size is more for anions having a more negative charge.

Hence, Ca^{2+}< K^+ < Ar < Cl^{-}< S^{2-}

Posted by

Sumit Saini

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