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Why is the bond order of  \mathrm{\mathrm{O}_2\left[\mathrm{AsF}_6\right] } higher than \mathrm{O}_2 ? 

Option: 1

The presence of \mathrm{AsF}_6  ligand in \mathrm{O}_2\left[\mathrm{AsF}_6\right] increases the electron density on the oxygen atoms, which results in a stronger bond.
 


Option: 2

The presence of \mathrm{AsF}_6 ligand in \mathrm{O}_2\left[\mathrm{AsF}_6\right] decreases the electron density on the oxygen atoms, which results in a weaker bond. 
 


Option: 3

The presence of A_s F_6 ligand in \mathrm{O}_2\left[\mathrm{AsF}_6\right] has no effect on the bond order of \mathrm{O}_2


Option: 4

None of the above


Answers (1)

best_answer

The \mathrm{AsF}_6 ligand is a strong electron-withdrawing ligand, which means that it pulls electrons away from the oxygen atoms in \mathrm{O}_2\left[\mathrm{AsF}_6\right]. This increases the electron density on the oxygen atoms, which results in a stronger bond.

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Gaurav

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