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1.0 mol of a monoatomic ideal gas is expanded from state (1) to state (2) as shown in figure. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K.

Answers (1)

We can conclude from the figure that this change is a reversible change.

Now,

W=-2.303\; nRT\; log\; p1/p2

= -2.303 \times 1 \times 8.314 \times 298 \times log \; 2

= -2.303 \times 8.314 \times 298 \times 0.3010\; J

=-1717.46\; J

The work done by an expanding gas is the energy required to move the gas against a force, and is calculated using the formula:

W=−PΔV

The negative sign in the formula indicates that the gas is doing work on its surroundings and losing energy in the process.

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