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  • A car of mass m starts from rest and acquires a velocity along east v = vi in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is a) mv/2 eastward and is exerted by the car engine

A car of mass m starts from rest and acquires a velocity along east v=v\widehat{i}  in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is

a) \frac{mv}{2} eastward and is exerted by the car engine

b) \frac{mv}{2} eastward and is due to the friction on the tyres exerted by the road

c) more than \frac{mv}{2} eastward exerted due to the engine and overcomes the friction of the road

d) \frac{mv}{2} exerted by the engine

Answers (1)

The answer is the option (b) \frac{mv}{2}  eastward and is due to friction on tyres exerted by the road.

Explanation: Here, u = 0, \overrightarrow{v} = vi, t = 2, m = m

We know that, v = u + at

\overrightarrow{v }\widehat{i}= 0 + \overrightarrow{a} \times 2

\overrightarrow{a} =\frac{\overrightarrow{v }\widehat{i}}{2}

\overrightarrow{F} = m\overrightarrow{a} = \frac{m\overrightarrow{v}}{2}\widehat{i}

The force by the engine is an internal force.

Posted by

infoexpert24

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