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A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field B. The work done to rotate the loop by 30^{\circ} about an axis perpendicular to its plane is

a) MB

b) \sqrt{3} \frac{MB}{}2

c) \frac{MB}{}2

d) zero

Answers (1)

The rotation of the loop by 30^{\circ} about an axis perpendicular to its plane make no change in the angle made by the axis of the loop with the direction of the magnetic field , therefore, the work done to rotate the loop is zero.

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infoexpert24

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