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A charged particle would continue to move with a constant velocity in a region wherein,

a) E = 0, B \neq 0

b) E \neq 0, B\neq 0

c) E \neq 0, B= 0

d)E = 0, B = 0

Answers (1)

The correct answers are the options (a, b, d).

F_{net} =qE + q(v \times B).

The force created by the electric field on the particle = qE

The force created by the magnetic field on the article F_{m}= q(v \times B)

As per the question, the acceleration of the particle is zero due to the constant velocity, and it is not changing its direction of motion. So, if the net force is zero -

(i) if E = 0, and v\parallel B, then F_{net} = 0.

(ii) ifE \neq 0, B\neq 0 and E, v and B are mutually perpendicular.

And (iii) when both E and B are absent.

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