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  • Consider a wire carrying a steady current, I placed un a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work.

Consider a wire carrying a steady current, I placed un a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work. This implies that

a) motion of charges inside the conductor is unaffected by B since they do not absorb energy

b) some charges inside the wire move to the surface as a result of B

c) if the wire moves under the influence of B, no work is done by the force

d) if the wire moves under the influence of B, no work is done by the magnetic force on the ions, assumed fixed within the wire

Answers (1)

The correction options are (b, d).

 The force experienced by a straight current-carrying conductor of length (l) at an angle \theta with the direction of the field placed in a uniform magnetic field (B) is Fmax= Bil sin θ. And the direction is determined by the right-hand palm rule.

 

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