Q : 15      A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs \small 200  for the first day, Rs \small 250 for the second day, Rs \small 300 for the third day, etc., the penalty for each succeeding day being Rs \small 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by \small 30 days?

Answers (1)
G Gautam harsolia

It is given that
Penalty for delay of completion beyond a certain date is Rs \small 200  for the first day, Rs \small 250 for the second day, Rs \small 300 for the third day and  penalty for each succeeding day being Rs \small 50 more than for the preceding day
We can clearly see that
200,250,300,..... is an AP  with 
a = 200 \ and \ d = 50
Now, the penalty for 30 days is given by the expression
S_{30}= \frac{30}{2}\left \{ 2\times 200+(30-1)50 \right \}
S_{30}= 15\left ( 400+1450 \right )
S_{30}= 15 \times 1850
S_{30}= 27750
Therefore, the penalty for 30 days is 27750

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