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A cricket bowler releases the ball in two different ways

a) giving it only horizontal velocity and

b) giving it horizontal velocity and a small downward velocity.

The speed vs at the time of release is the same. Both are released at a height H from the ground. Which one will have greater speed when the ball hits the ground? Neglect air resistance.

Answers (1)

(a)\frac{1}{2}v_{z}^{2} = gH

Thus,v_{z} =\sqrt{ 2gH}

Speed of the ball at ground =\sqrt{ v_{s}^{2}+v_{z}^{2} } = \sqrt{v_{s}^{2}+2gH}

(b) Here as well, the total energy of the ball when it hits the ground is \left [ \frac{1}{2} mv_{s}^{2} + mgH \right ]

Hence the speed is same for (a) as well as (b).

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