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A linearly polarized electromagnetic wave given as    E=E_0\hat{i}\cos\left ( kz-\omega t \right ) is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

(a)    E_r=E_0\hat{i}\cos\left ( kz+\omega t \right )

(b)    E_r=-E_0\hat{i}\cos\left ( kz-\omega t \right )

(c)    E_r=-E_0\hat{i}\sin\left ( kz-\omega t \right )

(d)    E_r=-E_0\hat{i}\cos\left ( kz+\omega t \right )

Answers (1)

The answer is the option (a)

E_r=E_0\hat{i}\cos\left ( kz+\omega t \right )

Solution: A wave used to be the same rather its phase changes by 180° or π radian when it is reflected from a denser medium or wall that is perfectly reflecting and made with optically inactive material.

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