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Get Answers to all your Questions
A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1 =N2 and Z2 =N1.
(a) What nuclide is a mirror isobar of 2311 Na?
(b) Which nuclide out of the two mirror isobars have greater binding energy and why?
Answers (1)
a) We can understand that a nuclide of 1 must be the mirror isobar of nuclide 2, when: Z1 = N2 and Z2 = N1
As a result, the mirror isobar is Z2 = 12 – N1
Similarly, N2 = 23 -12 = 11 = Z1
b) The binding energy of Mg is greater than Na.
View full answer
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