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  • A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m s^-2, what would be the reading of the weighing scale?

A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m s-2, what would be the reading of the weighing scale? (g = 10 ms2 )

 

Answers (1)

The apparent weight would decrease on the weighing scale if the lift is descending with an acceleration ‘a’.

Thus, W’ = R = (mg – ma)

                      = m (g – a)

Due to reaction force, apparent weight by the lift on the weighing scale would be,

W’ = 50 (10 – 9) =50 N

Thus, the reading of the weighing scale would be

\frac{R}{g}=\frac{50}{10}=5kg

Posted by

infoexpert24

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