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  • A pole 6 m high casts a shadow 2 sqroot 3 m long on the ground, then the Sun’s elevation is (A) 60° (B) 45° (C) 30° (D) 90°

A pole 6 m high casts a shadow 2\sqrt{3} m long on the ground, then the Sun’s elevation is

(A) 60°            (B) 45°            (C) 30°            (D) 90°

Answers (1)

Given:
height pole = 6 m 
Shadow of pole = 2\sqrt{3}m
Now make the figure according to the given condition

Let the angle of elevation is \alpha
\therefore \tan \alpha = \frac{Perpendicular}{base} 
\tan \alpha = \frac{6}{2\sqrt{3}}
\tan \alpha = \frac{3}{\sqrt{3}}= \sqrt{3}
\tan \alpha = \tan 60^{\circ}              \left [ \because \tan 60^{\circ}=\sqrt{3} \right ]
a = 60°
Hence the Sun's elevation is 60°.

Posted by

infoexpert27

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