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The value of the expression [cosec (75° + θ) – sec (15° – θ) – tan (55° + θ) + cot (35° – θ)] is
(A) – 1             (B) 0                (C) 1                (D)\frac{3}{2}

Answers (1)

Answer.        [B]      

Solution.      Given expression is :          
[cosec(75° + q) – sec (15° – q) – tan (55° + q) + cot (35° – q)]
[cosec(90 – (15 – q)) – sec (15° – q) – tan (90 – (35 – q)) + cot (35° – q)]
{\because we can write (75 + q) = (90 – (15 – q)) and (55 + q) =  (90 – (35 – q))}
{\because cosec (90 – q) = sec q and tan (90 – q) = cot q }

[sec(15 – q) – sec (15 – q) – cot (35 – q) + cot (35 – q)]=0
Hence option (B) is correct

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