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  • A woman throws an object of mass 500 g with a speed of 25 m s^1. (a) What is the impulse imparted to the object?

A woman throws an object of mass 500 g with a speed of 25 m s1.
(a) What is the impulse imparted to the object?
(b) If the object hits a wall and rebounds with half the original speed, what is the change in momentum of the
object?

Answers (1)

(a) Given: m = 500g

                     = 0.5 kg,

u =0 & v = 25 m/s.

We know that,                          

I = \Delta\overrightarrow{ P}

  = m (\overrightarrow{v} - \overrightarrow{u} )

  = 0.5 (25 – 0)

  = 12.5 N-s

(b) Here, m = 0.5 kg

                u = +25 ms-1 (forward)

                v = -\frac{25}{2}ms-1 (as backward)

Thus, \Delta p = m (v-u)

               = 0.5 \left [-\frac{25}{2} - 25 \right ]

                = 0.5 [ -12.5 – 25]

                = 0.5 \times (-37.5)

Therefore, \Delta p = -18.75 kg ms^{-1}

Therefore, \Delta por \frac{\Delta p}{\Delta t}  or the force is opposite to the initial velocity of the ball.

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