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AB is a current-carrying conductor in the plane of the paper as shown in Figure 13.7. What are the directions of magnetic fields produced by it at points P and Q? Given r1 > r2, where will the strength of the magnetic field be larger?

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Explanation:-
By using the right-hand thumb rule, we can find out the direction of the magnetic field due to a current-carrying wire. In the given diagram, the magnetic field lines will be a closed circular loop.
- By keeping the thumb along the current carrying wire, the direction can be deduced and it will be anticlockwise if we see it from above.
Therefore, magnetic field at point B will be into the plane of paper, and at point Q, it will be outside the plane of paper.
- As we go away from the wire, the magnetic field strength decreases in magnitude. Hence magnetic field strength will be
stronger at point B and weaker at point Q relatively.

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