Q : 8    An AP consists of \small 50 terms of  which \small 3rd term is \small 12 and the last term is \small 106. Find the \small 29th term.
 

Answers (1)

It is given that
AP consists of \small 50 terms of  which \small 3rd term is \small 12 and the last term is \small 106
Now,
a_3 = 12=a+2d \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -(i)
And
a_{50} = 106=a+49d \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -(ii)
On solving equation (i) and (ii) we will get 
a= 8 \ \ \ and \ \ \ d = 2
Now,
a_{29} = a+28d=8+28\times 2 = 8 +56 = 64
Therefore, 29th term of given AP is 64

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