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  • An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

Q 10.     An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

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Object distance u = -25 cm.

Focal length = 10 cm

Let image distance be v

\\\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\ \frac{1}{10}=\frac{1}{v}+\frac{1}{-25}\\ \frac{1}{v}=\frac{1}{10}+\frac{1}{25}\\ v=16. 66\ cm

Position of the image is 16.66 cm on the other side of the lens.

Object size O = 5 cm.

Let the image size be I

Magnification is m

\\m=\frac{v}{u}\\ \frac{I}{O}=\frac{16.66}{-25}\\ I=5\times -\frac{16.66}{25}\\ I=-3.33\ cm

The nature of the image is real and its size is -3.33 cm.

The formation of the image is shown in the following ray diagram

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