# Calculate the volume of water required to dissolve 0.1 g lead (II) chloride to get a saturated solution. (Ksp of PbCl2 = 3.2 x 10-8, atomic mass of Pb = 207 u).

As per the information available from the question, Ksp of PbCl2 = 3.2 ×10-8

Hence, we can write the equation of disassociation of PbCl2 as follows: -

 At t=0 1 0 0 At t=t 1-x x 2x

On substituting the given values, we get

We know that solubility is a product of molar mass

0.1g of  will be dissolved in 0.1798 L (0.1/0.0556)

Thus, 0.1798 is the required volume to get a saturated solution of

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