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  • Arrange the bases in decreasing order of the extent of their ionization at equilibrium. Which of the above base is the strongest?

Ionisation constant of a weak base MOH is given by the expression

K_{b}=\frac{[M^{+}][OH^{-}]}{[MOH]}

Values of ionization constant of some weak bases at a particular temperature are given below:

Base Dimethylamine Urea Pyridine Ammonia
  5.4\times 10^{-4} 1.3\times 10^{-14} 1.77\times 10^{-9} 1.77\times 10^{-5}

Arrange the bases in decreasing order of the extent of their ionization at equilibrium. Which of the above base is the strongest?

Answers (1)

As per the information available from the question, pKb values for Di-methylamine, ammonia, pyridine and urea are respectively 3.29, 4.752, 8.752, and 13.8861.

We know that, Higher is the value of Kb stronger will be the base. When we arrange then in decreasing order of extent of their ionization at equilibrium, they can be written as,

5.4\times 10^{-4} > 1.77\times 10^{-5} > 1.77\times 10^{-9} > 1.3\times 10^{-14}

So, the answer is Dimethylamine > Ammonia > Pyridine > Urea

Posted by

infoexpert22

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