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Conservation of momentum in a collision between particles can be understood from
(a) conservation of energy.
(b) Newton’s first law only.
(c) Newton’s second law only.
(d) both Newton’s second and third law.

Answers (1)

. The answer is the option (d) Both Newton’s second and third law

Explanation: (ii) \frac{\overrightarrow{dp}}{dt}=\overrightarrow{F}_{ext}                       ……. (By Newton’s second law)

 

 By the law of conservation of momentum

\overrightarrow{F}_{ext} =0

Thus, \frac{\overrightarrow{dp}}{dt}=0 hence,  \overrightarrow{p} = constant

 

(ii) Newton’s third law states that every action has an equal, opposite and instantaneous reaction, i.e., action force is equal to reaction force in magnitude but opposite in direction.

\overrightarrow{F}_{12}=-\overrightarrow{F}_{21}\left ( \overrightarrow{F}_{ext}=0 \right )

\frac{\overrightarrow{dp}_{12}}{dt}=-\frac{\overrightarrow{dp}_{21}}{dt}or \overrightarrow{dp}_{12}=-\overrightarrow{dp}_{21}

\overrightarrow{dp}_{12}+\overrightarrow{dp}_{21}=0

Hence, option (d).

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