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Describe the activity that shows that a current-carrying conductor experiences a force perpendicular to its length and the external magnetic field. How does Fleming’s left-hand rule help us to find the direction of the force acting on the current-carrying conductor?

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Explanation:-
Here we have a small aluminium rod AB. It is suspended horizontally from a stand, using two connecting wires.
A strong horse-shoe magnet is placed in such a way that the rod lies between the two poles with the magnetic field directed upwards.
The North Pole of the magnet lies vertically below and the South Pole lies vertically above the aluminium rod.
The rod is connected in series with a battery, a key and a rheostat.
The arrangement looks as:

Now if we pass a current through the aluminium rod from end B to end A, we observe that the rod is displaced towards left.
If we reverse the direction of the current, we observe that the direction of its displacement is now towards right.


This is explained using Fleming’s left-hand rule.
It states that: Stretch your thumb, forefinger and central finger of left hand such that they are mutually perpendicular. If the forefinger points in the direction of the magnetic field and the central finger points in the direction of current, then the thumb will point in the direction of motion or force acting on the conductor.
 

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