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Q3   Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear.

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Let the points (1, 5), (2, 3), and (- 2,-11) be representing the vertices A, B, and C of the given triangle respectively.

Let A = (1, 5), B = (2, 3) and C = (- 2,-11)

So The distance AB :

AB=\sqrt{(2-1)^2+(3-5)^2}

AB=\sqrt{1+4}

AB=\sqrt{5}

The distance BC :

BC=\sqrt{(-2-2)^2+(-11-3)^2}

BC=\sqrt{16+196}

BC=\sqrt{212}

The distance CA :

CA=\sqrt{(1-(-2))^2+(5-(-11))^2}

CA=\sqrt{9+256}

CA=\sqrt{265}

As we can see that  

AB + BC ≠ CA

Therefore, the points (1, 5), (2, 3), and ( - 2, - 11) are not collinear.

Posted by

Pankaj Sanodiya

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