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  • Differentiate each of the functions w.r. to x in 1/(ax^2+bx+c)

 Differentiate each of the functions w.r. to x in
\frac{1}{ax^{2}+bx+c}     

Answers (1)

The question involves the concept of chain rule

\\ Given\: \: that\: \: y=\frac{1}{ax^{2}+bx+c}= \left( ax^{2}+bx+c \right) ^{-1} \\ \\ \frac{dy}{dx}=-1 \left( ax^{2}+bx+c \right) ^{-2} \left( 2ax+b \right) =-\frac{2ax+b}{ax^{2}+bx+c} \\ \\

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infoexpert21

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