Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that triangle ABE similar to Delta CFB.

Q8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD  at F. Show that \Delta ABE \sim \Delta CFB

Answers (1)

best_answer

To prove : \Delta ABE \sim \Delta CFB

In \Delta ABE \, \, \, and\, \, \Delta CFB,

 \angle A=\angle C   ( Opposite angles of a parallelogram are equal)

\angle AEB=\angle CBF  ( Alternate angles of AE||BC)

\Delta ABE \sim \Delta CFB     ( By AA criterion ) 

 

Posted by

seema garhwal

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10 board exams 2026 from February 17, May 15; tentative date sheet out for both phases
anam-khan

CBSE launches Integrated Payment System for Class 10, 12 payments; holds principals liable for errors
anam-khan

NEP 2020 gives Indian schools space for new way of learning, with creativity, contemplation

Latest Question