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1.    Evaluate :

    (ii) \frac{\tan 26^{o}}{\cot 64^{o}}

Answers (1)

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\frac{\tan 26^{o}}{\cot 64^{o}}
The above equation can be written as ;

\tan (90^o-64^o)/\cot 64^o.........(i)
It is known that, \tan (90^o-\theta) = \cot \theta
Therefore, equation (i) becomes,
\cot64^o/\cot 64^o = 1

So, answer is 1.

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