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Q3 Factorise  

(I)

x ^ 2 + xy + 8 x + 8y

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best_answer

We have,
          x^2 = x \times x
          xy = x \times y 
          8x = 8 \times x
           8y = 8 \times y
Therefore,   on factorization we get,
x^2+xy+8x+8y = (x \times x)+(x\times y )+(8 \times x)+(8 \times y)
                                         = x(x +y )+8(x+ y)
                                         = (x+8)(x+y)
 

Posted by

Gautam harsolia

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