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Find the angle of elevation of the sun when the shadow of a pole h metres high is \sqrt{3} h metres long.

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Answer.       [30°]   
Solution.       According to question
 Here BC is the height of the pole i.e. h meters and AB is the length of shadow i.e. \sqrt{3}h .
 For finding angle q we have to find tanq in \bigtriangleupABC
\tan \theta = \frac{Perpendicular}{Base}
= \tan \theta = \frac{h}{\sqrt{3}h}
\theta = 30^{\circ}        \left ( \because \tan 30^{\circ}= \frac{1}{\sqrt{3}} \right )
Hence angle of elevation is 30°.

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