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  • Find the area of the triangle whose vertices are (–5, –1), (3, –5), (5, 2)

1.(ii)   Find the area of the triangle whose vertices are  (–5, –1), (3, –5), (5, 2)

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From the figure:

triangle area 2

Area of the triangle is given by:

Area = \frac{1}{2}\left [ x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2}) \right ]

Substituting the values in the above equation, we obtain

Area = \frac{1}{2}\left [ (-5)((-5)-(-2))+3(2-(1))+5(-1-(-5)) \right ]

= \frac{1}{2}\left [ 35+9+20 \right ] = 32 \ square\ units.

Posted by

Divya Prakash Singh

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