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Find the coefficient of x15 in the expansion of (x – x2)10
Answers (1)
Given: (x – x2)10
Thus, Tr+1 = 10Cr x10-r(-x2)r
= (-1)r 10Crx10-rx2r
= (-1)r 10Crx10+r
Now, for coefficient of x15
We have,
10 + r = 15
Thus, r = 5
Thus, T5+1 = (-1)5.10C5x15
Therefore,
Coefficient of x15 = -10x9x8x7x6x5!/5x4x3x2x1x5!
= -252
View full answer
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